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2x^2-25x=-63
We move all terms to the left:
2x^2-25x-(-63)=0
We add all the numbers together, and all the variables
2x^2-25x+63=0
a = 2; b = -25; c = +63;
Δ = b2-4ac
Δ = -252-4·2·63
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-11}{2*2}=\frac{14}{4} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+11}{2*2}=\frac{36}{4} =9 $
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